Aug 17, 2022by @kodeazy

How to re-try/catch a specific java code untill specific condition is reached?

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java

In this blog we will be discussing on how to re-try/catch a specific part of the code until the specific condition is reached.
lets take two variables as below
```
int num1=2,num2=0;
```
Now if we divide num1 with num2 we get java.lang.ArithmeticException: / by zero.

so in the below example we modify the value of num2 in catch block and re-try the condition by adding the whole code inside while loop.

import java.util.Random; 
class RetryCatchExample{
public static void main(String args[]){
	int num1=2,num2=0,divisionResult=0;
	boolean exit=false;
	while(!exit){
		try{
			divisionResult=num1/num2;
			System.out.println("Result after Execution :"+divisionResult);
			exit=true;

		}
		catch(Exception e){
			Random rand = new Random();
			System.out.println("You Got: "+e+" While Executing");
				if(num1<=0){
						num1=rand.nextInt(10);
				}
				else if(num2<=0){
					num2=rand.nextInt(10);
				}
				System.out.println("Re-trying to execute the Program after resolving the exception");
		}
	}
}
}

Output:

D:\java>javac RetryCatchExample.java
D:\java>java RetryCatchExample
You Got: java.lang.ArithmeticException: / by zero While Executing
Re-trying to execute the Program after resolving the exception
Result after Execution :0